高中生程式解題系統

#21875: #0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的答案為:

twm0970420996@gmail.com (小胖胖胖)

學校 : 不指定學校
編號 : 94884
來源 : [122.116.200.57]
最後登入時間：
2020-07-13 23:16:38

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [122.116.200.57] | 發表日期: 2020-07-28 22:55

#include <iostream>

using namespace std;

int cdefgab[8][10] ={

0,1,1,0,0,0,0,0,0,0,

0,1,0,0,0,0,0,0,0,0,

0,1,1,1,0,0,1,1,1,1,

0,1,1,1,0,0,1,1,1,0,

0,1,1,1,0,0,1,1,0,0,

0,1,1,1,0,0,1,0,0,0,

0,1,1,1,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,

};

int CDEFGAB[7][10]={

1,1,1,0,0,0,0,0,0,0,

1,1,0,0,0,0,0,0,0,0,

0,0,1,0,0,0,0,0,0,0,

1,1,1,1,0,0,1,1,1,0,

1,1,1,1,0,0,1,1,0,0,

1,1,1,1,0,0,1,0,0,0,

1,1,1,1,0,0,0,0,0,0,

};

int main(){

int t = 0 ;

int finger[10] = {0};

int *p, *lastp = cdefgab[7];

cin >> t;

while(t--){

for(int i = 0 ; i < 10 ;i++){

finger[i] = 0;

}

string song = "";

cin >> song ;

for(int i = 0 ; i < song.length() ; i++){

if(song[i] >= 'a' && song[i] <= 'g'){

p = cdefgab[song[i] - 'a'];

}

else if(song[i] >= 'A' && song[i] <= 'G'){

p = CDEFGAB[song[i] - 'A'];

}

for(int j = 0 ; j < 10 ; j++){

if(p[j] == 1 && ( lastp[j] == 0 || i == 0 )){

finger[j]++;

}

lastp = p;

}

for(int i = 0 ; i < 10 ; i++){

cout << finger[i] << " ";

}

cout << endl;

}

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#21876: Re:#0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的答

twm0970420996@gmail.com (小胖胖胖)

學校 : 不指定學校
編號 : 94884
來源 : [122.116.200.57]
最後登入時間：
2020-07-13 23:16:38

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [220.141.88.145] | 發表日期: 2020-07-28 22:56

#include

using namespace std;

int cdefgab[8][10] ={

0,1,1,0,0,0,0,0,0,0,

0,1,0,0,0,0,0,0,0,0,

0,1,1,1,0,0,1,1,1,1,

0,1,1,1,0,0,1,1,1,0,

0,1,1,1,0,0,1,1,0,0,

0,1,1,1,0,0,1,0,0,0,

0,1,1,1,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,

};

int CDEFGAB[7][10]={

1,1,1,0,0,0,0,0,0,0,

1,1,0,0,0,0,0,0,0,0,

0,0,1,0,0,0,0,0,0,0,

1,1,1,1,0,0,1,1,1,0,

1,1,1,1,0,0,1,1,0,0,

1,1,1,1,0,0,1,0,0,0,

1,1,1,1,0,0,0,0,0,0,

};

int main(){

int t = 0 ;

int finger[10] = {0};

int *p, *lastp = cdefgab[7];

cin >> t;

while(t--){

for(int i = 0 ; i < 10 ;i++){

finger[i] = 0;

}

string song = "";

cin >> song ;

for(int i = 0 ; i < song.length() ; i++){

if(song[i] >= 'a' && song[i] <= 'g'){

p = cdefgab[song[i] - 'a'];

}

else if(song[i] >= 'A' && song[i] <= 'G'){

p = CDEFGAB[song[i] - 'A'];

}

for(int j = 0 ; j < 10 ; j++){

if(p[j] == 1 && ( lastp[j] == 0 || i == 0 )){

finger[j]++;

}

}

lastp = p;

}

for(int i = 0 ; i < 10 ; i++){

cout << finger[i] << " ";

}

cout << endl;

}

}

請問是不是有什麼小細節沒有考慮到~?

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#21878: Re:#0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的答

IanWang20061204 (詭譎)

學校 : 臺北市立建國高級中學
編號 : 95399
來源 : [42.79.136.158]
最後登入時間：
2025-07-30 17:27:55

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [61.228.177.215] | 發表日期: 2020-07-29 10:08

#include

using namespace std;

int cdefgab[8][10] ={

0,1,1,0,0,0,0,0,0,0,

0,1,0,0,0,0,0,0,0,0,

0,1,1,1,0,0,1,1,1,1,

0,1,1,1,0,0,1,1,1,0,

0,1,1,1,0,0,1,1,0,0,

0,1,1,1,0,0,1,0,0,0,

0,1,1,1,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,

};

int CDEFGAB[7][10]={

1,1,1,0,0,0,0,0,0,0,

1,1,0,0,0,0,0,0,0,0,

0,0,1,0,0,0,0,0,0,0,

1,1,1,1,0,0,1,1,1,0,

1,1,1,1,0,0,1,1,0,0,

1,1,1,1,0,0,1,0,0,0,

1,1,1,1,0,0,0,0,0,0,

};

int main(){

int t = 0 ;

int finger[10] = {0};

int *p, *lastp = cdefgab[7];

cin >> t;

while(t--){

for(int i = 0 ; i < 10 ;i++){

finger[i] = 0;

}

string song = "";

cin >> song ;

for(int i = 0 ; i < song.length() ; i++){

if(song[i] >= 'a' && song[i] <= 'g'){

p = cdefgab[song[i] - 'a'];

}

else if(song[i] >= 'A' && song[i] <= 'G'){

p = CDEFGAB[song[i] - 'A'];

}

for(int j = 0 ; j < 10 ; j++){

if(p[j] == 1 && ( lastp[j] == 0 || i == 0 )){

finger[j]++;

}

}

lastp = p;

}

for(int i = 0 ; i < 10 ; i++){

cout << finger[i] << " ";

}

cout << endl;

}

}

請問是不是有什麼小細節沒有考慮到~?

有空白行

可以改成getline，或乾脆點string拿掉改成scanf也可以

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#21887: Re:#0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的答

753951852456 (精神小伙不請自來)

學校 : 臺北市私立延平高級中學
編號 : 103367
來源 : [203.72.178.3]
最後登入時間：
2022-04-13 12:40:32

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [203.72.178.1] | 發表日期: 2020-07-29 13:13

#include

using namespace std;

int cdefgab[8][10] ={

0,1,1,0,0,0,0,0,0,0,

0,1,0,0,0,0,0,0,0,0,

0,1,1,1,0,0,1,1,1,1,

0,1,1,1,0,0,1,1,1,0,

0,1,1,1,0,0,1,1,0,0,

0,1,1,1,0,0,1,0,0,0,

0,1,1,1,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,

};

int CDEFGAB[7][10]={

1,1,1,0,0,0,0,0,0,0,

1,1,0,0,0,0,0,0,0,0,

0,0,1,0,0,0,0,0,0,0,

1,1,1,1,0,0,1,1,1,0,

1,1,1,1,0,0,1,1,0,0,

1,1,1,1,0,0,1,0,0,0,

1,1,1,1,0,0,0,0,0,0,

};

int main(){

int t = 0 ;

int finger[10] = {0};

int *p, *lastp = cdefgab[7];

cin >> t;

while(t--){

for(int i = 0 ; i < 10 ;i++){

finger[i] = 0;

}

string song = "";

cin >> song ;

for(int i = 0 ; i < song.length() ; i++){

if(song[i] >= 'a' && song[i] <= 'g'){

p = cdefgab[song[i] - 'a'];

}

else if(song[i] >= 'A' && song[i] <= 'G'){

p = CDEFGAB[song[i] - 'A'];

}

for(int j = 0 ; j < 10 ; j++){

if(p[j] == 1 && ( lastp[j] == 0 || i == 0 )){

finger[j]++;

}

}

lastp = p;

}

for(int i = 0 ; i < 10 ; i++){

cout << finger[i] << " ";

}

cout << endl;

}

}

請問是不是有什麼小細節沒有考慮到~?

有空白行

可以改成getline，或乾脆點string拿掉改成scanf也可以

簡單

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#21921: Re:#0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的答

twm0970420996@gmail.com (小胖胖胖)

學校 : 不指定學校
編號 : 94884
來源 : [122.116.200.57]
最後登入時間：
2020-07-13 23:16:38

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [111.252.137.48] | 發表日期: 2020-07-30 22:30

#include

using namespace std;

int cdefgab[8][10] ={

0,1,1,0,0,0,0,0,0,0,

0,1,0,0,0,0,0,0,0,0,

0,1,1,1,0,0,1,1,1,1,

0,1,1,1,0,0,1,1,1,0,

0,1,1,1,0,0,1,1,0,0,

0,1,1,1,0,0,1,0,0,0,

0,1,1,1,0,0,0,0,0,0,

0,0,0,0,0,0,0,0,0,0,

};

int CDEFGAB[7][10]={

1,1,1,0,0,0,0,0,0,0,

1,1,0,0,0,0,0,0,0,0,

0,0,1,0,0,0,0,0,0,0,

1,1,1,1,0,0,1,1,1,0,

1,1,1,1,0,0,1,1,0,0,

1,1,1,1,0,0,1,0,0,0,

1,1,1,1,0,0,0,0,0,0,

};

int main(){

int t = 0 ;

int finger[10] = {0};

int *p, *lastp = cdefgab[7];

cin >> t;

while(t--){

for(int i = 0 ; i < 10 ;i++){

finger[i] = 0;

}

string song = "";

cin >> song ;

for(int i = 0 ; i < song.length() ; i++){

if(song[i] >= 'a' && song[i] <= 'g'){

p = cdefgab[song[i] - 'a'];

}

else if(song[i] >= 'A' && song[i] <= 'G'){

p = CDEFGAB[song[i] - 'A'];

}

for(int j = 0 ; j < 10 ; j++){

if(p[j] == 1 && ( lastp[j] == 0 || i == 0 )){

finger[j]++;

}

}

lastp = p;

}

for(int i = 0 ; i < 10 ; i++){

cout << finger[i] << " ";

}

cout << endl;

}

}

請問是不是有什麼小細節沒有考慮到~?

有空白行

可以改成getline，或乾脆點string拿掉改成scanf也可以

簡單

請問這跟空白行有什麼關西@@

我用uva原文測資是對的

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#53718: Re: #0: 50% WA (line:5) 您的答案為: 1 2 6 1 0 0 1 1 1 0 正確答案為: 0 0 0 0 0 0 0 0 0 0 #1: 50% WA (line:5) 您的

pofly (不挖鼻孔有害身心健康)

學校 : 不指定學校
編號 : 322682
來源 : [123.192.228.253]
最後登入時間：
2025-10-11 19:00:08

e531. 10415 - Eb Alto Saxophone Player -- UVA

| From: [123.192.228.253] | 發表日期: 2025-09-27 09:51

請問這跟空白行有什麼關西@@

我用uva原文測資是對的

五年了過去了，但我想應該也會有人有一樣的疑惑

這題的空行不能跳過

空行代表的是空字串，意思是「這是一首沒有任何音符的歌」

還是要處理，但因為根本沒有按任何音符，所以輸出的部分理所當然就是一連串的 0 了

使用 std::cin 會跳過那一行，導致原本應該讀 t 次測資的程式會少讀幾組測資。

因為 std::cin 讀取失敗時不會報錯......只會改變 std::cin 的狀態標籤

讀取失敗時，對應的變量會維持原樣，不修改其內容

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